CASE function

Hi,
I have a date column where the application users puposely enter a date way
in the future as part of their business rule. For instance, entering the yea
r
2033 if the given value for this date column is unknown.
I need to programmatically retrieve this date and represent those
out-of-whack dates to show as the current date + 10 days.
I created the following SELECT stmt. using the CASE function:
SELECT ....
CASE post_datetime
WHEN post_datetime > getdate()+365 THEN getdate()+10
...
However, SQL QA returns an error (Incorrect syntax near '>') when I try to
execute this stmt. What am I doing wrong here. Please help. Thanks.
Regards,
- Rob.Rob wrote:
> Hi,
> I have a date column where the application users puposely enter a date way
> in the future as part of their business rule. For instance, entering the y
ear
> 2033 if the given value for this date column is unknown.
> I need to programmatically retrieve this date and represent those
> out-of-whack dates to show as the current date + 10 days.
> I created the following SELECT stmt. using the CASE function:
> SELECT ....
> CASE post_datetime
> WHEN post_datetime > getdate()+365 THEN getdate()+10
> ...
> However, SQL QA returns an error (Incorrect syntax near '>') when I try to
> execute this stmt. What am I doing wrong here. Please help. Thanks.
> Regards,
> - Rob.
Try this instead:
CASE WHEN post_datetime > GETDATE() + 365 THEN GETDATE() + 10 ELSE
post_datetime END|||> SELECT ....
> CASE post_datetime
> WHEN post_datetime > getdate()+365 THEN getdate()+10
There are two general forms of the CASE expression (it is not a function).
You can either say
CASE [expression] WHEN [value] THEN [value] END
or
CASE WHEN [expression][operator][value] THEN [value] END
You combined the two in a way I don't recall ever seeing (and as you have
found out, the syntax is invalid). You need the latter, because you are
testing a more complex expression than simple equality.
Try:
SELECT
CASE WHEN post_datetime > getdate()+365 THEN getdate()+10 ENDsql